如何根据时间段得出不同部门的累计异常工时
如何根据时间段得出不同部门的累计异常工时,谢谢公式:=24*SUMPRODUCT((E$3:E$10=G3)*MID(D$3:D$10,{1,7},5)*{-1,1})
这公式只能针对前者时间小于后者。
数组公式:
=24*SUM((E$3:E$10=G3)*(IF(RIGHT(D$3:D$10,5)<LEFT(D$3:D$10,5),RIGHT(D$3:D$10,5)+1,RIGHT(D$3:D$10,5))-LEFT(D$3:D$10,5)))
H3=24*SUMPRODUCT((E$3:E$10=G3)*((MID(D$3:D$10,{1,7},5)*{-1,1})+(MMULT(MID(D$3:D$10,{1,7},5)*1,{-1;1})<0)*{0,1})) =SUMPRODUCT(MOD(MMULT(IMREAL(IMDIV($D$3:$D$10&"i",{1,"-i"})),{-1;1}),1)*($E$3:$E$10=G3))*24
时间格式标准可=SUMPRODUCT(MOD(MMULT(-MID($D$3:$D$10,{1,7},5),{1;-1}),1)*($E$3:$E$10=G3))*24 =MOD(SUMPRODUCT((E$3:E$10=G3)*MID(D$3:D$10,{1,7},5)*{-1,1})*24,24)
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